Chương 3: PHƯƠNG TRÌNH, HỆ PHƯƠNG TRÌNH
Các câu hỏi tương tự
Giải hpt \(\left\{{}\begin{matrix}\sqrt{y+3x}+\sqrt{2x+7y}=\sqrt{5x-y}+3\sqrt{x}\\x-4-\sqrt{y-2}=\sqrt{x^3-10x^2+33x-34}-\sqrt{y^3-9y^2+24y-16}\end{matrix}\right.\)
giải hpt: \(\left\{{}\begin{matrix}\sqrt{xy+\left(x-y\right)\left(\sqrt{xy}-2\right)}+\sqrt{x}=y+\sqrt{y}\\\left(x+1\right)\left(y+\sqrt{xy}+x-x^2\right)=4\end{matrix}\right.\)
giải hpt
\(\left\{{}\begin{matrix}\sqrt{x}\left(\sqrt{x+3}+\sqrt{x}\right)=3\\\sqrt{x}+\sqrt{y}=x+1\end{matrix}\right.\)
giải hpt
\(\left\{{}\begin{matrix}\sqrt{x}+\sqrt[4]{32-x}-y^2+3=0\\\sqrt{32-x}+\sqrt[4]{x}+6y=24\end{matrix}\right.\)
1.Giải hpt bằng pp thêm bớt hằng số để nhân liên hợp
a,\(\left\{{}\begin{matrix}\sqrt{x^2-x-y}=\dfrac{y}{\sqrt[3]{x-y}}\\2\left(x^2+y^2\right)-3\sqrt{2x-1}=11\end{matrix}\right.\)
giải giúp mik bt này vs mn!
1)left{{}begin{matrix}2x^2+y^2+x3left(xy+1right)+2ydfrac{2}{3+sqrt{2x-y}}+dfrac{2}{3+sqrt{4-5x}}dfrac{9}{2x-y+9}end{matrix}right.
2)left{{}begin{matrix}left(x+3y+1right)sqrt{2xy+2y}yleft(3x+4y+3right)left(sqrt{x+3}-sqrt{2y-2}right)left(x-3+sqrt{x^2+x+2y-4}right)4end{matrix}right.
3)left{{}begin{matrix}x-dfrac{1}{x}y-dfrac{1}{y}2yx^3+1end{matrix}right.
4)left{{}begin{matrix}sqrt{2x-3}left(y^2+2011right)left(5-yright)+sqrt{y}yleft(y-x+2right)3x+3end{matrix}right.
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giải giúp mik bt này vs mn!
1)\(\left\{{}\begin{matrix}2x^2+y^2+x=3\left(xy+1\right)+2y\\\dfrac{2}{3+\sqrt{2x-y}}+\dfrac{2}{3+\sqrt{4-5x}}=\dfrac{9}{2x-y+9}\end{matrix}\right.\)
2)\(\left\{{}\begin{matrix}\left(x+3y+1\right)\sqrt{2xy+2y}=y\left(3x+4y+3\right)\\\left(\sqrt{x+3}-\sqrt{2y-2}\right)\left(x-3+\sqrt{x^2+x+2y-4}\right)=4\end{matrix}\right.\)
3)\(\left\{{}\begin{matrix}x-\dfrac{1}{x}=y-\dfrac{1}{y}\\2y=x^3+1\end{matrix}\right.\)
4)\(\left\{{}\begin{matrix}\sqrt{2x-3}=\left(y^2+2011\right)\left(5-y\right)+\sqrt{y}\\y\left(y-x+2\right)=3x+3\end{matrix}\right.\)
5)\(\left\{{}\begin{matrix}x^3+2x^2=x^2y+2xy\\2\sqrt{x^2-2y-1}+\sqrt[3]{y^3-14=x-2}\end{matrix}\right.\)
1.Giải hpt : a,\(\left\{{}\begin{matrix}\left(x+y+3\right)\sqrt{x-2y}+2y+4=0\\\left(x-y\right)\left(x^2+4\right)=y^2+1\end{matrix}\right.\)
giải hệ phương trình:
1, \(\left\{{}\begin{matrix}x-2y-\sqrt{xy}=0\\\sqrt{x-1}-\sqrt{2y-1}=1\end{matrix}\right.\)
2, \(\left\{{}\begin{matrix}\sqrt{11x-y}-\sqrt{y-x}=1\\7\sqrt{y-x}+6y-26x=3\end{matrix}\right.\)
3, \(\left\{{}\begin{matrix}\left(y-3\right)\sqrt{xy}+2y\sqrt{x}-4\sqrt{y}-2y+6=0\\y^4-xy^3+xy=4\end{matrix}\right.\)
giúp mik giải bài hệ pt vs ạ!
1,left{{}begin{matrix}x^2+y^2+dfrac{2xy}{x+y}1sqrt{x+y}x^2-yend{matrix}right.
2,left{{}begin{matrix}2x^3+xy^2+xy^3+4x^2y+2ysqrt{4x^2+x+6}-5sqrt{1+2y}1-4yend{matrix}right.
3,left{{}begin{matrix}2x^2+sqrt{2}xleft(x+yright)y+sqrt{x+y}sqrt{x-1}+xysqrt{y^2+21}end{matrix}right.
4,left{{}begin{matrix}sqrt{9y^2+left(2y+3right)left(y-xright)}+4sqrt{xy}7xleft(2y-1right)sqrt{1+x}+left(2y+1right)sqrt{1-x}2yend{matrix}right.
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giúp mik giải bài hệ pt vs ạ!
1,\(\left\{{}\begin{matrix}x^2+y^2+\dfrac{2xy}{x+y}=1\\\sqrt{x+y}=x^2-y\end{matrix}\right.\)
2,\(\left\{{}\begin{matrix}2x^3+xy^2+x=y^3+4x^2y+2y\\\sqrt{4x^2+x+6}-5\sqrt{1+2y}=1-4y\end{matrix}\right.\)
3,\(\left\{{}\begin{matrix}2x^2+\sqrt{2}x=\left(x+y\right)y+\sqrt{x+y}\\\sqrt{x-1}+xy=\sqrt{y^2+21}\end{matrix}\right.\)
4,\(\left\{{}\begin{matrix}\sqrt{9y^2+\left(2y+3\right)\left(y-x\right)}+4\sqrt{xy}=7x\\\left(2y-1\right)\sqrt{1+x}+\left(2y+1\right)\sqrt{1-x}=2y\end{matrix}\right.\)