Question

giải hộ mk câu này

\(\left(x^2+1\right)\left(x^2-4x+4\right)=0\)

Answer 1

Giải:

\(\left(x^2+1\right)\left(x^2-4x+4\right)=0\)

\(\Leftrightarrow\left(x^2+1\right)\left(x-2\right)^2=0\)

Vì \(x^2+1\ge1>0\forall x\)

Nên \(\left(x-2\right)^2=0\)

\(\Leftrightarrow x-2=0\)

\(\Leftrightarrow x=2\)

Vậy ...

Answer 2

⇒(x²+1) (x-2) = 0

⇒\(\left[{}\begin{matrix}x^2+1=0\\x-2=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x^2=-1\left(otm\right)\\x=2\left(tm\right)\end{matrix}\right.\)