Question

Giải hệ PT

\(\left\{{}\begin{matrix}3x-2y=6\\x+2y=10\end{matrix}\right.\)

Answer 1

\(\left\{{}\begin{matrix}3x-2y=6\\x+2y=10\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}4x=16\\x+2y=10\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}x=4\\4+2y=10\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}x=4\\y=3\end{matrix}\right.\)

Answer 2

\(\left\{{}\begin{matrix}3x-2y=6\\x+2y=10\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}4x=16\\x+2y=10\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=4\\y=3\end{matrix}\right.\)

Vậy nghiệm hệ phương trình là $(4;3)$