Question

Giải giúp mk câu này!!!!!Gấp nha vì mai mk khảo sát rùiiiiiii!!!!

Answer 1

Ta có:

\(\sqrt{2-\sqrt{3}}\)

\(=\sqrt{\dfrac{2\left(2-\sqrt{3}\right)}{2}}\)

\(=\sqrt{\dfrac{4-2\sqrt{3}}{2}}\)

\(=\sqrt{\dfrac{3-2\sqrt{3}+1}{2}}\)

\(=\sqrt{\dfrac{\left(\sqrt{3}-1\right)^2}{2}}\)

\(=\dfrac{\left|\sqrt{3}-1\right|}{\sqrt{2}}\)

\(=\dfrac{\sqrt{3}-1}{\sqrt{2}}\) (vì \(\sqrt{3}-1>0\))

\(=\dfrac{\sqrt{3}}{\sqrt{2}}-\dfrac{1}{\sqrt{2}}\)

\(=\sqrt{\dfrac{3}{2}}-\sqrt{\dfrac{1}{2}}\)

Yêu cầu bài toán \(\Leftrightarrow\left\{{}\begin{matrix}x=\dfrac{3}{2}\\y=\dfrac{1}{2}\end{matrix}\right.\) (thỏa mãn)

Vậy \(\left\{{}\begin{matrix}x=\dfrac{3}{2}\\y=\dfrac{1}{2}\end{matrix}\right.\) thỏa mãn yêu cầu bài toán.