\(4,\Rightarrow3x-\dfrac{11}{4}=-\dfrac{1}{3}\\ \Rightarrow3x=-\dfrac{1}{3}+\dfrac{11}{4}=\dfrac{29}{12}\\ \Rightarrow x=\dfrac{29}{12}\cdot\dfrac{1}{3}=\dfrac{29}{36}\)
\(5,\Rightarrow-x-\dfrac{5}{24}=-2+\dfrac{1}{4}x\\ \Rightarrow-\dfrac{3}{4}x=-\dfrac{43}{24}\\ \Rightarrow x=-\dfrac{43}{24}\cdot\left(-\dfrac{4}{3}\right)=\dfrac{43}{18}\)
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