Question

Giúp mình với ạ mình đang cần gấp ạ cảm ơn

Answer 1

1) \(\left(\dfrac{-13}{17}-\dfrac{31}{52}\right)-\left(\dfrac{73}{52}-\dfrac{13}{17}+\dfrac{5}{6}\right)-\dfrac{3}{4}\)

\(=\dfrac{-13}{17}-\dfrac{31}{52}-\dfrac{73}{52}+\dfrac{13}{17}-\dfrac{5}{6}-\dfrac{3}{4}\)

\(=\left(\dfrac{-13}{17}+\dfrac{13}{17}\right)-\left(\dfrac{31}{52}+\dfrac{73}{52}\right)-\left(\dfrac{5}{6}+\dfrac{3}{4}\right)\)

\(=0-2-\dfrac{19}{12}\)

\(=-2-\dfrac{19}{12}\)

\(=\dfrac{-43}{12}\)

Answer 2

2) \(\dfrac{1}{7}.\dfrac{1}{3}+\dfrac{1}{7}.\dfrac{1}{2}-\dfrac{1}{7}\)

\(=\dfrac{1}{7}\left(\dfrac{1}{3}+\dfrac{1}{2}-1\right)\)

\(=\dfrac{1}{7}.-\dfrac{1}{6}\)

\(=-\dfrac{1}{42}\)

Answer 3

3) \(\dfrac{13}{123}.\dfrac{1}{2}-\dfrac{1}{3}.\dfrac{13}{123}+\dfrac{1}{6}.\dfrac{110}{123}\)

\(=\dfrac{13}{123}.\left(\dfrac{1}{2}-\dfrac{1}{3}\right)+\dfrac{1}{6}.\dfrac{110}{123}\)

\(=\dfrac{13}{123}.\dfrac{1}{6}+\dfrac{1}{6}.\dfrac{110}{123}\)

\(=\dfrac{1}{6}\left(\dfrac{13}{123}+\dfrac{110}{123}\right)\)

\(=\dfrac{1}{6}.\dfrac{123}{123}\)

\(=\dfrac{1}{6}\)

Answer 4

2/ \(\dfrac{1}{7}.\dfrac{1}{3}+\dfrac{1}{7}.\dfrac{1}{2}-\dfrac{1}{7}\)

= \(\dfrac{1}{7}\left(\dfrac{1}{3}+\dfrac{1}{2}-1\right)\)

= \(\dfrac{1}{7}\left(\dfrac{2}{6}+\dfrac{3}{6}-\dfrac{6}{6}\right)\)

= \(\dfrac{1}{7}.\dfrac{-1}{6}\)

= \(\dfrac{1.\left(-1\right)}{7.6}\)

= \(\dfrac{-1}{42}\)