ĐKXĐ: ....
\(\Leftrightarrow\sqrt{2x^2+5x+2}=1+2\sqrt{2x^2+5x-6}\)
\(\Leftrightarrow2x^2+5x+2=4\left(2x^2+5x-6\right)+1+4\sqrt{2x^2+5x-6}\)
\(\Leftrightarrow3\left(2x^2+5x-6\right)+4\sqrt{2x^2+5x-6}-7=0\)
Đặt \(\sqrt{2x^2+5x-6}=a\ge0\)
\(3a^2+4a-7=0\Rightarrow\left[{}\begin{matrix}a=1\\a=-\frac{7}{3}\left(l\right)\end{matrix}\right.\)
\(\Rightarrow\sqrt{2x^2+5x-6}=1\Leftrightarrow2x^2+5x-7=0\)