\(\frac{1}{x}-\frac{1}{y}=\frac{1}{4}\Leftrightarrow\frac{y-x}{xy}=\frac{1}{4}\Leftrightarrow\frac{x-y}{64}=\frac{1}{4}\Leftrightarrow4\left(x-y\right)=64\Leftrightarrow x-y=16\)
\(\Rightarrow x=16+y\left(1\right)\)
Mà \(xy=-64\left(2\right)\)
Thay (1) vào (2) ta có \(\left(16+y\right)\cdot y=-64\Leftrightarrow16y+y^2=-64\Leftrightarrow y^2+16y+64=0\Leftrightarrow\left(y+8\right)^2=0\Leftrightarrow y+8=0\Leftrightarrow y=-8\)
Suy ra \(x=16+y=16-8=8\)