\(\Leftrightarrow\dfrac{x}{a}-x>4-a-\dfrac{3}{a}\)
\(\Leftrightarrow x\left(\dfrac{1}{a}-1\right)>\dfrac{4a-a^2-3}{a}\)
- Nếu \(\dfrac{1}{a}-1>0\Leftrightarrow0< a< 1\)
\(\Rightarrow x>\dfrac{4a-a^2-3}{a\left(\dfrac{1}{a}-1\right)}\Leftrightarrow x>a-3\)
- Nếu \(\dfrac{1}{a}-1< 0\Leftrightarrow\left[{}\begin{matrix}a< 0\\a>1\end{matrix}\right.\)
\(\Rightarrow x< \dfrac{4a-a^2-3}{a\left(\dfrac{1}{a}-a\right)}\Leftrightarrow x< a-3\)