Question

giá trị tuyệt đối của x+5 + (3y-4)^2018=0

Answer 1

\(\left|x+5\right|+\left(3y-4\right)^{2018}=0\)

Lại có : \(\left\{{}\begin{matrix}\left|x+5\right|\ge0\\\left(3y-4\right)^{2018}\ge0\end{matrix}\right.\)

\(\Leftrightarrow\left|x+5\right|+\left(3y-4\right)^{2018}\ge0\)

Dấu "=" xảy ra khi :

\(\left\{{}\begin{matrix}\left|x+5\right|=0\\\left(3y-4\right)^{2018}=0\end{matrix}\right.\) \(\Leftrightarrow\left\{{}\begin{matrix}x-5=0\\3y-4=0\end{matrix}\right.\) \(\Leftrightarrow\left\{{}\begin{matrix}x=5\\y=\dfrac{4}{3}\end{matrix}\right.\)

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