\(\left(1-2x\right)\left(x-3\right)\)
\(=x-3-2x^2+6x\)
\(=-2x^2+7x-3\)
\(=-2\left(x^2-\dfrac{7}{2}x+\dfrac{3}{2}\right)\)
\(=-2\left(x^2-2\cdot x\cdot\dfrac{7}{4}+\dfrac{49}{16}-\dfrac{1}{16}\right)\)
\(=-2\left(x-\dfrac{7}{4}\right)^2+\dfrac{1}{8}< =\dfrac{1}{8}\)
Dấu '=' xảy ra khi x=7/4