Question

giá trị của biểu thức \(\frac{\left(1+\frac{2017}{1}\right)\left(1+\frac{2017}{2}\right)...\left(1+\frac{2017}{1009}\right)}{\left(1+\frac{1009}{1}\right)\left(1+\frac{1009}{2}\right)...\left(1+\frac{1009}{2007}\right)}\) là.....

Answer 1

1

tick mình nha thank

Answer 2

\(\frac{\left(1+\frac{2017}{1}\right)\left(1+\frac{2017}{2}\right)....\left(1+\frac{2017}{1009}\right)}{\left(1+\frac{1009}{1}\right)\left(1+\frac{1009}{2}\right)....\left(1+\frac{1009}{2017}\right)}=\frac{1.1.1.....1}{1.1.1....1}=1\)

Answer 3

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