Question

Giá trị của biểu thức \(B=\left(x^{2007}+3x^{2006}-1\right)^{2007}\) tại \(x=-3\) là B =

Answer 1

Tại x= - 3

=> \(B=\left[\left(-3\right)^{2017}+3\left(-3\right)^{2016}-1\right]^{2017}\)

=> \(B=\left[\left(-3\right)^{2017}+3^{2017}-1\right]^{2017}\)

=> \(B=\left(-1\right)^{2017}\)

=> B = - 1

Answer 2

Ta có:

\(B=\left(x^{2007}+3x^{2006}-1\right)^{2007}\)

\(B=\left(\left(-3\right)^{2007}+3\left(-3\right)^{2006}-1\right)^{2007}\)

\(B=\left(\left(-3\right)^{2007}+3\left(3\right)^{2006}-1\right)^{2007}\)

\(B=\left(\left(-3\right)^{2007}+3^1\left(3\right)^{2006}-1\right)^{2007}\)

\(B=\left(\left(-3\right)^{2007}+3^{1+2006}-1\right)^{2007}\)

\(B=\left(\left(-3\right)^{2007}+3^{2007}-1\right)^{2007}\)

\(B=\left(0-1\right)^{2007}\)

\(B=\left(-1\right)^{2007}\)

\(B=1\)

Answer 3

\(B=\left(x^{2007}+3x^{2006}-1\right)^{2007}\)

\(\Rightarrow B=\left[\left(-3\right)^{2007}+3.\left(-3\right)^{2006}-1\right]^{2007}\)

\(\Rightarrow B=\left[\left(-3\right)^{2006}.\left(3+\left(-3\right).1\right)-1\right]^{2007}\)

\(\Rightarrow B=\left[\left(-3\right)^{2006}.0-1\right]^{2007}\)

\(\Rightarrow B=\left(0-1\right)^{2007}\)

\(\Rightarrow B=-1^{2007}\)

\(\Rightarrow B=-1\)