Question

gấp ạ 5h kém mk phải noppj r ạ

Answer 1

Bài 2: 

a: Ta có: \(\sqrt{2x-15}=3\)

\(\Leftrightarrow2x-15=9\)

\(\Leftrightarrow2x=24\)

hay x=12

b: Ta có: \(\sqrt{x^2-2x+1}=5\)

\(\Leftrightarrow\left|x-1\right|=5\)

\(\Leftrightarrow\left[{}\begin{matrix}x-1=5\\x-1=-5\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=6\\x=-4\end{matrix}\right.\)