\(=\frac{x\sqrt{x}+26\sqrt{x}-19-2\sqrt{x}\left(\sqrt{x+3}\right)+\left(\sqrt{x}-3\right)\left(\sqrt{x}-1\right)}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+3\right)}\) (ĐKXĐ: \(x\ne1;x\ge0\))
\(=\frac{x\sqrt{x}+26\sqrt{x}-19-2x-6\sqrt{x}+x-4\sqrt{x}+3}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+3\right)}\)
\(=\frac{x\sqrt{x}+16\sqrt{x}-x-16}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+3\right)}=\frac{x-16}{\sqrt{x}+3}\) (Biểu thức được rút gọn với ĐKXĐ)
ĐKXĐ: x\(\ge0;x\ne1\)
\(=\frac{x\sqrt{x}+26\sqrt{x}-19}{x+2\sqrt{x}-3}-\frac{2\sqrt{x}\left(\sqrt{x}+3\right)+\left(\sqrt{x}-3\right)\left(\sqrt{x}-1\right)}{x+2\sqrt{x}-3}\)
\(=\frac{x\sqrt{x}+26\sqrt{x}-19-2x-6\sqrt{x}-x+\sqrt{x}+3\sqrt{x}-3}{x+2\sqrt{x}-3}\)
\(=\frac{x\sqrt{x}+24\sqrt{x}-3x-22}{x+2\sqrt{x}-3}\)
Đến đây chả bt đúng hay sai :D
