\(\frac{9y-13}{8}+\frac{-5y+5}{8}=\frac{9y-13-5y+5}{8}=\frac{4y-8}{8}=4y-1.\)
Chúc bạn học tốt!
cho mình xin lỗi tính lộn bước
\(\frac{4y-8}{8}\)
=\(\frac{4\left(y-2\right)}{4\times2}\)
=\(\frac{y-2}{2}\)
nhớ rút gọn giùm mik nha
\(=\frac{4y-8}{8}=\frac{4\left(x-2\right)}{4\cdot2}=\frac{x-2}{2}\)
\(\frac{9y-13}{8}+\frac{-5y+5}{8}\)
=\(\frac{9y-13-5y+5}{8}\)
=\(\frac{4y-8}{8}\)
=\(\frac{4\left(y-8\right)}{4\times2}\)
=\(\frac{y-8}{2}\)