3/(x2+x-2) -1/(x-1) =-7/(x+2)
(=) 3/(x-1)(x+2) -(x+2)/(x+2)(x-1) +7(x-1)/(x-1)(x+2)=0
(=) 3 - x - 2 + 7x -7 = 0
(=) 6x = 6
(=) x= 1
vậy S={1}
Chúc bạn học tốt.
Bài 5: Phương trình chứa ẩn ở mẫu
Các câu hỏi tương tự
f.\(\frac{3}{x^2+x-2}-\frac{1}{x-1}=\frac{-7}{x+2}\)
g.\(\frac{2}{-x^2+6x-8}-\frac{x-1}{x-2}=\frac{x+3}{x-4}\)
h.\(\frac{2}{x^3-x^2-x+1}=\frac{3}{1-x^2}-\frac{1}{x-1}\)
i.\(\frac{x+2}{x-2}-\frac{2}{x^2-2x}=\frac{1}{x}\)
j.\(\frac{5}{-x^2+5x-6}+\frac{x+3}{2-x}=0\)
Giari các phương trình sau.
a. frac{1}{x}+frac{1}{x+10}frac{1}{12}
b. frac{x+3}{x-3}-frac{1}{x}frac{3}{xleft(x-3right)}
c. frac{3}{x+2}-frac{2}{x-2}+frac{8}{x^2-4}0
d. frac{3}{x+2}-frac{2}{x-3}frac{8}{left(x-3right)left(x+2right)}
e. frac{x}{2x+6}-frac{x}{2x+2}frac{3x+2}{left(x+1right)left(x+3right)}
f. frac{x}{x+1}-frac{2x-3}{1-x}frac{3x^2+5}{x^2-1}
g. frac{5}{x+7}+frac{8}{2x+14}frac{3}{2}
h. frac{x-1}{x}-frac{1}{x+1}frac{2x-1}{x^2+x}
Đọc tiếp
Giari các phương trình sau.
a. \(\frac{1}{x}+\frac{1}{x+10}=\frac{1}{12}\)
b. \(\frac{x+3}{x-3}-\frac{1}{x}=\frac{3}{x\left(x-3\right)}\)
c. \(\frac{3}{x+2}-\frac{2}{x-2}+\frac{8}{x^2-4}=0\)
d. \(\frac{3}{x+2}-\frac{2}{x-3}=\frac{8}{\left(x-3\right)\left(x+2\right)}\)
e. \(\frac{x}{2x+6}-\frac{x}{2x+2}=\frac{3x+2}{\left(x+1\right)\left(x+3\right)}\)
f. \(\frac{x}{x+1}-\frac{2x-3}{1-x}=\frac{3x^2+5}{x^2-1}\)
g. \(\frac{5}{x+7}+\frac{8}{2x+14}=\frac{3}{2}\)
h. \(\frac{x-1}{x}-\frac{1}{x+1}=\frac{2x-1}{x^2+x}\)
a.\(\frac{x+1}{x-1}-\frac{x-1}{x+1}=\frac{16}{x^2-1}\)
b.\(\frac{12}{x^2-4}-\frac{x+1}{x-2}+\frac{x+7}{x+2}=0\)
c.\(\frac{12}{8-x^3}=1+\frac{1}{x+2}\)
d.\(\frac{x+25}{2x^2-50}-\frac{x+5}{x^2-5x}=\frac{5-x}{2x^2+10x}\)
e.\(\frac{4}{x^2+2x-3}=\frac{2x-5}{x+3}-\frac{2x}{x-1}\)
a) frac{7x-3}{x-1}frac{2}{3}
b) frac{1}{x-2}+3frac{3-x}{x-2}
c) frac{8-x}{x-7}-8frac{1}{x-7}
d) frac{x+5}{x-5}-frac{x-5}{x+5}frac{20}{x^2-25}
e) frac{x}{2left(x-3right)}+frac{x}{2left(x+1right)}frac{2x}{left(x+1right)left(x-3right)}
f) frac{1}{x}+frac{1}{x+10}frac{1}{12}
Mong mọi người giúp đỡ ~~ __
Đọc tiếp
a) \(\frac{7x-3}{x-1}=\frac{2}{3}\)
b) \(\frac{1}{x-2}+3=\frac{3-x}{x-2}\)
c) \(\frac{8-x}{x-7}-8=\frac{1}{x-7}\)
d) \(\frac{x+5}{x-5}-\frac{x-5}{x+5}=\frac{20}{x^2-25}\)
e) \(\frac{x}{2\left(x-3\right)}+\frac{x}{2\left(x+1\right)}=\frac{2x}{\left(x+1\right)\left(x-3\right)}\)
f) \(\frac{1}{x}+\frac{1}{x+10}=\frac{1}{12}\)
Mong mọi người giúp đỡ >~~< >__<
\(\frac{4}{-25x^2+20x-3}=\frac{3}{5x-1}-\frac{2}{5x-3}\)
\(\frac{1}{x^2-3x+2}+\frac{1}{x^2-5x+6}-\frac{2}{x^2-4x+3}=0\)
\(\frac{x-1}{2x^2-4x}-\frac{7}{8x}=\frac{5-x}{4x^2-8x}-\frac{1}{8x-16}\)
\(\frac{1}{x^2+9x+20}+\frac{1}{x^2+11x+30}+\frac{1}{x^2+13x+42}=\frac{1}{18}\)
a)\(\frac{5}{x+7}+\frac{8}{2x+14}=\frac{3}{2}\)
b)\(\frac{x+3}{x-3}-\frac{1}{x}=\frac{3}{x\left(x-3\right)}\)
c)\(\frac{1}{x}+\frac{1}{x+10}=\frac{1}{12}\)
d)\(\frac{90}{x}-\frac{36}{x-36}=2\)
c)\(\frac{x}{x+1}-\frac{2x-3}{1-x}=\frac{3x^2+5}{x^2-1}\)
12 tháng 2 2020 lúc 19:31
a) \(\frac{1}{x-4}-\frac{2+x}{x+4}=\frac{x\left(7-x\right)}{x^2-16}\)
b) \(\frac{1}{x-1}+\frac{2x^2-5}{x^3-1}=\frac{4}{x^2+x+1}\)
1, giải pt sau
a,\(\frac{9}{x}+2=-6\)
b,\(\frac{7}{x+1}+\frac{-18x}{x\left(x^2+4x+3\right)}=\frac{-4}{x+3}\)
c,\(\frac{3x-1}{x-1}-1=\frac{2x+5}{x+3}+\frac{4}{x^2+2x-3}\)
help meeeeeee!!!!!!
giải phương trình :
a) 3x(x-1)=(x-1)(x+2)
b) \(\frac{4x+3}{5}-\frac{6x-2}{7}=\frac{5x+4}{3}+3\)
c) \(\frac{1}{2}\left(x+1\right)+\frac{1}{4}\left(x+3\right)=3-\frac{1}{2}\left(x+2\right)\)
d) ** \(\frac{x+2}{98}+\frac{x+4}{96}=\frac{x+6}{94}+\frac{x+8}{92}\) ưu tiên câu d nha