Question

\(\frac{3-X}{2018}\)+\(\frac{x-1}{2020}\)=\(\frac{-X}{2021}\)+1

Answer 1

bn ơi, X với x giống nhau đúng ko, nếu mà X với x là một thì sẽ làm như này:

\(\frac{3-x}{2018}+\frac{x-1}{2020}=\frac{-x}{2021}+1\)

\(\Leftrightarrow\) \(\frac{3-x}{2018}+1+\frac{x-1}{2020}-1=\frac{-x}{2021}+1+1-1\)

\(\Leftrightarrow\) \(\frac{2021-x}{2018}-\frac{2021-x}{2020}=\frac{2021-x}{2021}\)

\(\Leftrightarrow\) \(\frac{2021-x}{2018}-\frac{2021-x}{2020}-\frac{2021-x}{2021}=0\)

\(\Leftrightarrow\) (2021 - x)(\(\frac{1}{2018}-\frac{1}{2020}-\frac{1}{2021}\)) = 0

\(\Leftrightarrow\) 2021 - x = 0

\(\Leftrightarrow\) x = 2021

Vậy S = {2021}

Chúc bn học tốt!!