\(=\frac{2\sqrt{3-\sqrt{3+\sqrt{\left(2\sqrt{3}+1\right)^2}}}}{\sqrt{6}-\sqrt{2}}=\frac{2\sqrt{3-\sqrt{4+2\sqrt{3}}}}{\sqrt{6}-\sqrt{2}}\)
\(=\frac{2\sqrt{3-\sqrt{\left(\sqrt{3}+1\right)^2}}}{\sqrt{6}-\sqrt{2}}=\frac{2\sqrt{2-\sqrt{3}}}{\sqrt{6}-\sqrt{2}}=\frac{\sqrt{2}.\sqrt{4-2\sqrt{3}}}{\sqrt{2}\left(\sqrt{3}-1\right)}\)
\(=\frac{\sqrt{\left(\sqrt{3}-1\right)^2}}{\sqrt{3}-1}=1\)