Ta có: \(-\frac{22}{15}x+\frac{1}{3}=\left|-\frac{2}{3}+\frac{1}{5}\right|\)
hay \(-\frac{22}{15}x=\frac{7}{15}-\frac{1}{3}=\frac{2}{15}\)
\(\Leftrightarrow x=\frac{2}{15}:\frac{-22}{15}=\frac{2}{15}\cdot\frac{15}{-22}=\frac{-2}{22}=\frac{-1}{11}\)
Vậy: \(x=\frac{-1}{11}\)
\(-\frac{22}{15}x+\frac{1}{3}=\left|-\frac{2}{3}+\frac{1}{5}\right|\)
\(\Rightarrow-\frac{22}{15}x+\frac{1}{3}=\left|-\frac{7}{15}\right|\)
\(\Rightarrow-\frac{22}{15}x+\frac{1}{3}=\frac{7}{15}\)
\(\Rightarrow-\frac{22}{15}x=\frac{7}{15}-\frac{1}{3}\)
\(\Rightarrow-\frac{22}{15}x=\frac{2}{15}\)
\(\Rightarrow x=\frac{2}{15}:\left(-\frac{22}{15}\right)\)
\(\Rightarrow x=-\frac{1}{11}\)
Vậy \(x=-\frac{1}{11}.\)
Chúc bạn học tốt!
