Giải phương trình sau:
a) \(\frac{10}{\left(x+5\right)\left(x-1\right)}+\frac{3}{1-x}=\frac{5}{x+5}\)
b) \(\frac{x-1}{x+2}+\frac{x+3}{x-4}=\frac{2}{\left(x-2\right)\left(4-x\right)}\)
c) \(\frac{7x-3}{x-x^3}=\frac{1}{x-1}-\frac{5}{x\left(x-1\right)}\)
d) \(\frac{1}{\left(x+2\right)}+\frac{1}{\left(x+3\right)}=\frac{1}{\left(x+2\right)\left(x+3\right)}\)
Giải phương trình sau:
a) \(\frac{10}{\left(x+5\right)\left(x-1\right)}+\frac{3}{1-x}=\frac{5}{x+3}\)
b) \(\frac{x-1}{x+2}+\frac{x+3}{x-4}=\frac{2}{\left(x-2\right)\left(4-x\right)}\)
c) \(\frac{7x-3}{x-x^3}=\frac{1}{x-1}-\frac{5}{x\left(x-1\right)}\)
d) \(\frac{1}{x+2}+\frac{1}{x+3}=\frac{1}{\left(x+2\right)\left(x+3\right)}\)
Giải phương trình sau:
a) \(\frac{10}{\left(x+5\right)\left(x-1\right)}+\frac{3}{1-x}=\frac{5}{x+5}\)
b) \(\frac{x-1}{x+2}+\frac{x+3}{x-4}=\frac{2}{\left(x-2\right)\left(4-x\right)}\)
c) \(\frac{7x-3}{x-x^3}=\frac{1}{x-1}-\frac{5}{\left(x-1\right)}\)
d) \(\frac{1}{x+2}+\frac{1}{x+3}=\frac{1}{\left(x+2\right)\left(x+3\right)}\)
\(20\left(\frac{x-2}{x+1}\right)^2-3\left(\frac{x+2}{x-1}\right)^2+48\left(\frac{x^2-4}{x^2-1}\right)=0\)
Giup vơi!!
Giải phương trình sau:
a) \(\frac{x-1}{x-2}+\frac{x+3}{x-4}=\frac{2}{\left(x-2\right)\left(4-x\right)}\)
b) \(\frac{7x-3}{x-x^3}=\frac{1}{x-1}-\frac{5}{x\left(x-1\right)}\)
c) \(\frac{15}{x^2+x-12}+\frac{2}{x-3}=\frac{1}{x+4}\)
d) \(\frac{3}{x-2}+\frac{3}{x-3}-\frac{1}{x^2-5x=6}=3\)
Giải bất phương trình
a) x3 - 6x2 + 5x + 12 >0
b) \(\frac{5x\left(2x+1\right)\left(5-x\right)}{\left(x+3\right)\left(3x-4\right)}>0\)
c) \(\frac{1}{2-3}>\frac{2}{1+4x}\)
d) \(\frac{1}{x}+\frac{2}{x+2}< \frac{3}{x+1}\)
e) 3x3 - 14x2 + 20x >8
f) x5 - x4 + x3 - x2 + x - 1<0
g) (x - 1)(x - 3)(x + 5)(x + 7)<297
h) x4 - 2x3 + x >132
Giải bpt sau
a, \(\left(x+3\right)^2-\left(x-3\right)^2\le3\left(x+1
\right)\)
b, \(2\left(x+3\right).\left(x+4\right)>\left(x-2\right)^2+\left(x-1\right)^2\)
c, \(5x^2-18x+19-\left(2x-3\right)^2>0\)
d, \(\dfrac{\left(3x-2\right)^2}{4}-\dfrac{3\left(x-2\right)}{8}-1>\dfrac{-15x\left(5-3x\right)}{2}\)
e, \(2x^2+2x+2-\dfrac{15\left(x-1\right)}{2}-1>2x\left(x-2,75\right)\)
g, \(\dfrac{5x^2-3}{5}+\dfrac{3x-1}{4}< \dfrac{x\left(2x+3\right)}{2}-5\)
Bài 1:
a) ( x + 1 )( x - 3 ) ≤ 0
b) \(\left(x^2+1\right)\left(x-2\right)\) ≥ 0
Bài 2:
a) \(\frac{x-2}{x+1}< 0\)
b) \(\frac{-2}{x-1}>0\)
c) \(\frac{x-1}{x+3}>0\)
d)\(\frac{x^2-x+1}{x+3}>0\)
e) \(\frac{x-2}{x+1}\) ≤ 0
f) \(\frac{x^2}{x-3}\) ≥ 0
Giải phương trình sau:
a) \(\frac{1}{x-1}+\frac{2}{x^2+x+1}=\frac{3x^2}{x^3-1}\)
b) \(\frac{1}{2-x}+1=\frac{1}{x+2}-\frac{6-x}{3x^2-12}\)
c) \(\frac{x-2}{x+2}+\frac{3}{2-x}=\frac{2\left(x-11\right)}{x^2-4}\)
d) \(x^2-6x-2+\frac{14}{x^2-6x+7}=0\)