Violympic toán 9
Các câu hỏi tương tự
Tìm GTLN:
\(A=\frac{\sqrt{10x-49}}{2020}\\ B=\frac{\sqrt{2x^2-25}}{2020x^2}\\ C=\frac{7x^8+256}{x^7}\left(x>0\right)\\ D=\frac{\sqrt{x}+6\sqrt{x}+34}{\sqrt{x}+3}\\ E=x+\frac{1}{x-1}\left(x>1\right)\)
Bài 1 :
\(X=\left(\frac{1+2\sqrt{x}}{4+2\sqrt{x}}+\frac{\sqrt{x}}{6-3\sqrt{x}}+\frac{2x}{12-3x}\right).\frac{24-12\sqrt{x}}{6+13\sqrt{x}}\)
a, Tìm ĐKXĐ
b, Rút gọn
c, Tìm x để X < \(\frac{4}{6-3\sqrt{x}}\)
Giúp mk với !!!
24 tháng 3 2020 lúc 8:55
Giải phương trình:
a) \(\sqrt{\frac{2x-1}{x+1}}+\sqrt{\frac{x+1}{2x-1}}=2\)
b) \(2\sqrt[3]{\frac{2x-3}{1-x}}+\sqrt[3]{\frac{1-x}{2x-3}}=3\)
c) \(x+\frac{1}{x}+4\left(\sqrt{x}+\frac{1}{\sqrt{x}}\right)+6=0\)
LARGE 7)Gfrac{sqrt{x}+1}{x-1}+frac{sqrt{x}-1}{sqrt{x}+1}-frac{2sqrt{x}+2}{x-1}Gfrac{sqrt{x}+1}{sqrt{x}-1}+frac{sqrt{x}-1}{sqrt{x}+1}-frac{2(sqrt{x}+1)}{(sqrt{x}-1)(sqrt{x}+1)}Gfrac{sqrt{x}+1}{x-1}+frac{sqrt{x}-1}{sqrt{x}+1}-frac{2}{sqrt{x}-1}Gfrac{(sqrt{x}+1)^2+(sqrt{x}-1)^2-2(sqrt{x}+1)}{(sqrt{x}-1)(sqrt{x}+1)}Gfrac{2x-2sqrt{x}}{(sqrt{x}-1)(sqrt{x}+1)}Gfrac{2sqrt{x}(sqrt{x}-1)}{(sqrt{x}-1)(sqrt{x}+1)}Gfrac{2sqrt{x}}{sqrt{x}+1}8)H(frac{1}{sqrt{x}-1}+frac{sqrt{x}}{x-1}):(frac{sqrt{x}}{sqrt{x}-1}-...
Đọc tiếp
\[\LARGE 7)G=\frac{\sqrt{x}+1}{x-1}+\frac{\sqrt{x}-1}{\sqrt{x}+1}-\frac{2\sqrt{x}+2}{x-1}\\G=\frac{\sqrt{x}+1}{\sqrt{x}-1}+\frac{\sqrt{x}-1}{\sqrt{x}+1}-\frac{2(\sqrt{x}+1)}{(\sqrt{x}-1)(\sqrt{x}+1)}\\G=\frac{\sqrt{x}+1}{x-1}+\frac{\sqrt{x}-1}{\sqrt{x}+1}-\frac{2}{\sqrt{x}-1}\\G=\frac{(\sqrt{x}+1)^2+(\sqrt{x}-1)^2-2(\sqrt{x}+1)}{(\sqrt{x}-1)(\sqrt{x}+1)}\\G=\frac{2x-2\sqrt{x}}{(\sqrt{x}-1)(\sqrt{x}+1)}\\G=\frac{2\sqrt{x}(\sqrt{x}-1)}{(\sqrt{x}-1)(\sqrt{x}+1)}\\G=\frac{2\sqrt{x}}{\sqrt{x}+1}\\8)H=(\frac{1}{\sqrt{x}-1}+\frac{\sqrt{x}}{x-1}):(\frac{\sqrt{x}}{\sqrt{x}-1}-1)\\H=(\frac{1}{\sqrt{x}-1}+\frac{\sqrt{x}}{(\sqrt{x}-1)(\sqrt{x}+1)}):(\frac{\sqrt{x}-(\sqrt{x}-1)}{\sqrt{x}-1})\\H=\frac{\sqrt{x}+1+\sqrt{x}}{(\sqrt{x}-1)(\sqrt{x}+1)}:\frac{\sqrt{x}-\sqrt{x}+1}{\sqrt{x}-1}\\H=\frac{2\sqrt{x}+1}{(\sqrt{x}-1)(\sqrt{x}+1)}:\frac{1}{\sqrt{x}-1}\\H=\frac{2\sqrt{x}+1}{(\sqrt{x}-1)(\sqrt{x}+1)}.(\sqrt{x}-1)\\H=\frac{2\sqrt{x}}{\sqrt{x}+1}\]
Tính
3) \(\frac{\sqrt{x}-1}{\sqrt{x}+1}+\frac{2x-\sqrt{x}-1}{x-\sqrt{x}+1}-\frac{3x\sqrt{x}-2x+\sqrt{x}-3}{x\sqrt{x}+1}\)
4) \(\frac{15\sqrt{x}-11}{x+2\sqrt{x}-3}-\frac{3\sqrt{x}-2}{\sqrt{x}-1}-\frac{2\sqrt{x}+3}{\sqrt{x}+3}\)
5)\(\frac{\sqrt{x}-1}{\sqrt{x}-3}-\frac{\sqrt{x}+3}{\sqrt{x}-2}-\frac{x+5}{x-5\sqrt{x}+6}\)
Help !!! Mk đang cần gấp ,thank các ben
bài 1: giải pt
a. \(\sqrt{x-1}+\sqrt{2x-1}=5\)
b. \(x+\sqrt{2x-1}-2=0\)
bài 2: tính
A=\(\sqrt{7-4\sqrt{3}}-\sqrt{7+4\sqrt{3}}\)
B=\(\sqrt{15-6\sqrt{6}}+\sqrt{33-12\sqrt{6}}\)
C=\(\left(\frac{1}{3-\sqrt{5}}-\frac{1}{3+\sqrt{5}}\right)\).\(\frac{\sqrt{5}-1}{5-\sqrt{5}}\)
Giải phương trình vô tỉ:
a) 1+frac{2}{3}sqrt{x-x^2}sqrt{x}+sqrt{1-x}
b) sqrt{2x+3}+sqrt{x+1}3x+2sqrt{2x^2+5x+3}-2
c) sqrt{7x+7}+sqrt{7x-6}+2sqrt{49x^2+7x-42}181-4x
d) frac{sqrt{x+4}+sqrt{x-4}}{2}x+sqrt{x^2-16}-6
e) 5sqrt{x}+frac{5}{2sqrt{x}}2x+frac{1}{2x}+4
g) sqrt{3x-2}+sqrt{x-1}4x-9+2sqrt{3x^2-5x+2}
Đọc tiếp
Giải phương trình vô tỉ:
a) \(1+\frac{2}{3}\sqrt{x-x^2}=\sqrt{x}+\sqrt{1-x}\)
b) \(\sqrt{2x+3}+\sqrt{x+1}=3x+2\sqrt{2x^2+5x+3}-2\)
c) \(\sqrt{7x+7}+\sqrt{7x-6}+2\sqrt{49x^2+7x-42}=181-4x\)
d) \(\frac{\sqrt{x+4}+\sqrt{x-4}}{2}=x+\sqrt{x^2-16}-6\)
e) \(5\sqrt{x}+\frac{5}{2\sqrt{x}}=2x+\frac{1}{2x}+4\)
g) \(\sqrt{3x-2}+\sqrt{x-1}=4x-9+2\sqrt{3x^2-5x+2}\)
Giải phương trình:
\(a)\sqrt{x^2+2x+4}\ge x-2\\ b)x=\sqrt{x-\frac{1}{x}}+\sqrt{x+\frac{1}{x}}\\ c)\sqrt{x+2+3\sqrt{2x-5}}+\sqrt{x-2\sqrt{2x-5}}\\ d)x+y+z+4=2\sqrt{x-2}+4\sqrt{y-3}+6\sqrt{z-5}\\ e)\sqrt{x}+\sqrt{y-1}+\sqrt{z-2}=\frac{1}{2}\left(x+y+z\right)\)
a. A(frac{3x+16sqrt{x}-7}{x+2sqrt{x}-3}-frac{sqrt{x}+1}{sqrt{x}+3}-frac{sqrt{x}+7}{sqrt{x}-1}) : (2-frac{sqrt{x}}{sqrt{x}-1})
b. B(frac{sqrt{x}+1}{sqrt{xy}+1}+frac{sqrt{xy}+sqrt{x}}{1-sqrt{xy}}+1) :( 1-frac{sqrt{xy}+sqrt{x}}{sqrt{xy}-1}-frac{sqrt{x}+1}{sqrt{xy}+1})
c. C( frac{sqrt{x}-4x}{1+4x}-1):(frac{1+2x}{1-4x}-frac{2sqrt{x}}{2sqrt{x}}-1)
d. D(frac{sqrt{a-b}}{sqrt{a+b}+sqrt{a+b}}+frac{a-b}{sqrt{a^2-b^2}-a+b})frac{a^2+b^2}{sqrt{a^2-b^2}}
e. Efrac{left(sqrt{a}-sqrt{b}right)+4sqrt{ab}}{sqrt{...
Đọc tiếp
a. A=(\(\frac{3x+16\sqrt{x}-7}{x+2\sqrt{x}-3}-\frac{\sqrt{x}+1}{\sqrt{x}+3}-\frac{\sqrt{x}+7}{\sqrt{x}-1}\)) : (\(2-\frac{\sqrt{x}}{\sqrt{x}-1}\))
b. B=(\(\frac{\sqrt{x}+1}{\sqrt{xy}+1}+\frac{\sqrt{xy}+\sqrt{x}}{1-\sqrt{xy}}+1\)) :( 1-\(\frac{\sqrt{xy}+\sqrt{x}}{\sqrt{xy}-1}-\frac{\sqrt{x}+1}{\sqrt{xy}+1}\))
c. C=( \(\frac{\sqrt{x}-4x}{1+4x}-1\)):(\(\frac{1+2x}{1-4x}-\frac{2\sqrt{x}}{2\sqrt{x}}-1\))
d. D=(\(\frac{\sqrt{a-b}}{\sqrt{a+b}+\sqrt{a+b}}+\frac{a-b}{\sqrt{a^2-b^2}-a+b}\))\(\frac{a^2+b^2}{\sqrt{a^2-b^2}}\)
e. E=\(\frac{\left(\sqrt{a}-\sqrt{b}\right)+4\sqrt{ab}}{\sqrt{a}+\sqrt{b}}-\frac{a\sqrt{b}-b\sqrt{a}}{\sqrt{ab}}-b\)