Question

\(\frac{-3}{4}-x=\frac{2}{5}\)

\(\frac{-4}{x}=\frac{x}{-16}\)

Answer 1

+) \(\frac{-3}{4}-x=\frac{2}{5}\)

=> \(-x=\frac{2}{5}+\frac{3}{4}\)

=> \(-x=\frac{23}{20}\)

=> \(x=\frac{-23}{20}\)

Vậy \(x=\frac{-23}{20}\)

+) \(\frac{-4}{x}=\frac{x}{-16}\)

=> \(x.x=-4.\left(-16\right)\)

=> \(x^2=64\)

=> \(x=\sqrt{64}=8\)

hoặc \(x=-\sqrt{64}=-8\)

Vậy \(x=8\) hoặc \(x=-8\)

Answer 2

\(\frac{-3}{4}-x=\frac{2}{5}\)

\(\Rightarrow x=\frac{-3}{4}-\frac{2}{5}=\frac{-15}{20}-\frac{8}{20}=-\frac{23}{20}\)

Vậy: \(x=-\frac{23}{20}\)

\(\frac{-4}{x}=\frac{x}{-16}\)

\(\Rightarrow x^2=-4.-16=64\)

\(\Rightarrow x=\sqrt{64}=\pm8\)

Vậy: \(x=\pm8\)