\(x^2-10x=-25\)
\(x^2-10x+25=0\)
\(x^2-2.x.5+5^2=0\)
\(\left(x-5\right)^2=0\)
\(\left(x-5\right)=0\)
\(x=0+5\)
\(x=5\)
\(\Rightarrow x^2-2.5.x+5^2=0\)
\(\Rightarrow\left(x-5\right)^2=0\)
\(\Rightarrow x-5=0\)
=> x=5
Vậy x = 5
f) \(x^2-10x=-25\)
\(\Leftrightarrow x^2-10x+25=0\)
\(\Leftrightarrow\left(x-5\right)^2=0\)
\(\Leftrightarrow x-5=0\)
\(\Leftrightarrow x=5\)