\(4Al+3O2-->2Al2O3\)
\(n_{O2}=\frac{13,44}{22,4}=0,6\left(mol\right)\)
\(n_{Al}=\frac{4}{3}n_{O2}=0,8\left(mol\right)\)
\(m=m_{Al}=0,8.27=21,6\left(g\right)\)
\(n_{Al2O3}=\frac{2}{3}n_{O2}=0,4\left(mol\right)\)
\(m_1=m_{Al2O3}=0,4.102=40,8\left(g1\right)\)
\(4Al+3O_2\rightarrow2Al_2O_3\)
\(n_{O_2}=\frac{13.44}{22.4}\approx0.6\left(mol\right)\)
\(n_{Al}=\frac{4}{3}\cdot n_{O_2}=\frac{4}{3}\cdot0.6=0.8\left(mol\right)\)
\(\Rightarrow m_{Al}=0.8\cdot27=21.6\left(g\right)\)
\(n_{Al_2O_3}=\frac{2}{3}\cdot n_{O_2}=\frac{2}{3}\cdot0.6=0.4\left(mol\right)\)
\(\Rightarrow m1_{Al_2O_3}=0.4\cdot102=40.8\left(g\right)\)
