Ta có:
\(n_C=n_{CO2}=\frac{17,6}{44}=0,4\left(mol\right)\)
\(n_H=n_{H2O}=\frac{9}{18}=1\left(mol\right)\)
\(m_O=7,4-0,4.12-1=1,6\left(g\right)\)
\(\Rightarrow n_O=\frac{1,6}{16}=0,1\left(mol\right)\)
\(n_C:n_H:n_O=0,4:1:0,1=4:10:1\)
Vậy CTPT là C4H10O
CTCT dạng thu gọn : CH3−CH2−CH2−CH2−OH