\(PTHH:4P+5O_2\rightarrow2P_2O_5\)
Ta có :
\(n_{O2}=\frac{8,96}{22,4}=0,4\left(mol\right)\)
\(\rightarrow m_{O2}=0,4.32=12,8\left(g\right)\)
Áp dụng ĐL bảo toàn KL:
\(m_P+m_{O2}=m_{P2O5}\)
\(m_{P2O5}=6,2+12,8=19\left(g\right)\)
Vì H = 80 %
\(\rightarrow m_{P2O5}=\frac{19.80}{100}=15,2\left(g\right)\)