\(n_{Fe}=\dfrac{11,2}{56}=0,2\left(mol\right)\)
PT: \(3Fe+2O_2\underrightarrow{t^o}Fe_3O_4\)
Theo PT: \(n_{O_2}=\dfrac{2}{3}n_{Fe}=\dfrac{2}{15}\left(mol\right)\Rightarrow V_{O_2}=\dfrac{2}{15}.22,4=\dfrac{224}{75}\left(l\right)\)
\(\Rightarrow V_{kk}=\dfrac{V_{O_2}}{20\%}=\dfrac{224}{15}\left(l\right)\)
\(n_{Fe}=\dfrac{11,2}{56}=0,2\left(mol\right)\)
\(PTHH:4Fe+3O_2\xrightarrow[t^0]{}2Fe_2O_3\)
tỉ lệ :4 3 2
số mol :0,2 0,15 0,1
\(V_{O_2}=0,1.22,4=2,24\left(l\right)\)
\(V_{kk}=2,24.20\%=0,448\left(l\right)\)