2C2H2(x) + 5O2(2,5x) → 4CO2(2x) + 2H2O
CH4(y) + 2O2(2y) → CO2(y) + 2H2O
Ta có : x + y = 24 => y = 24 - x
2,5x + 2y = 54
=> 2,5x + 2(24 - x) = 54
=> x = 12(ml)
=> y = 12(ml)
a)
%C2H2 = 12 . 100% : 24 = 50%
%CH4 = 100% - 50% = 50%
b) VCO2 = 2x + y = 36(ml)