a)1,3(12)=\(\dfrac{1}{10}.\left(13+12.\dfrac{1}{99}\right)\)=\(\dfrac{443}{330}\)
b)\(3,3\left(21\right)=\dfrac{1}{10}\left(33+21.\dfrac{1}{99}\right)=\dfrac{548}{165}\)
c)\(5,2\left(24\right)=\dfrac{1}{10}\left(52+24.\dfrac{1}{99}\right)=\dfrac{862}{165}\)
d)\(3,32\left(6\right)=\dfrac{1}{100}\left(332+6.\dfrac{1}{9}\right)=\dfrac{499}{150}\)
A, 1,3(12) = \(\dfrac{433}{330}\)
B, 3,3(21) = \(\dfrac{548}{165}\)
C,5,2(24) = \(\dfrac{862}{165}\)
D,3,32(6) = \(\dfrac{499}{150}\)
A, 1,3(12)=\(\dfrac{433}{330}\)
B, 3,3(21)= \(\dfrac{548}{165}\)
C, 5,2(24)= \(\dfrac{862}{165}\)
D, 3,32(6)= \(\dfrac{499}{150}\)