300ml = 0,3l
\(n_{NaCl}=0,2.0,3=0,06\left(mol\right)\)
Pt : \(2NaCl+H_2O\rightarrow\left(dpcmn\right)2NaOH+H_2+Cl_2|\)
2 1 2 1 1
0,06 0,06
\(n_{H2}\dfrac{0,06.1}{1}=0,06\left(mol\right)\)
\(V_{H2\left(dktc\right)}=0,06.22,4=1,344\left(l\right)\)
⇒ Chọn câu : C
Chúc bạn học tốt
Chọn C
PTHH
2NaCL + H2O ----> 2NaOH + H2 + Cl2
0,06 -------------------------------0,03---0,03
theo pthh: n H2 = n CL2 = 0,03 ( mol )
=> V khí = 0,03 . 2 . 22,4 = 1,344
\(NaCl+H_2O\) \(\underrightarrow{đpddcmnx}\) \(NaOH+\dfrac{1}{2}H_2+\dfrac{1}{2}Cl_2\)
nNaCl= 0,3. 0,2=0,06(mol)
=> \(n_{H_2}+n_{Cl_2}=\dfrac{0,06}{2}+\dfrac{0,06}{2}=0,06\left(mol\right)\)
\(\rightarrow V_{khí\left(đktc\right)}=0,06.22,4=1,344\left(l\right)\)
=> Chọn C