\(\dfrac{x+3}{-15}=\dfrac{1}{3}\)
\(\Leftrightarrow\dfrac{x+3}{-15}=\dfrac{-5}{-15}\)
\(\Leftrightarrow x+3=-5\)
\(\Leftrightarrow x=-8\)
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Ôn tập chương III
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Bài 1: Tìm x, biếta) 3dfrac{1}{3} x+ 16dfrac{3}{4} -13,25b) 3dfrac{2}{7}.x - dfrac{1}{8} 2dfrac{3}{4} c) x : 4dfrac{1}{3} - 2,5d) (dfrac{3x}{7} + 1) : (-4) dfrac{-1}{28}giúp em
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Bài 1: Tìm x, biết
a) 3\(\dfrac{1}{3}\) x+ 16\(\dfrac{3}{4}\) = -13,25
b) 3\(\dfrac{2}{7}\).x - \(\dfrac{1}{8}\) = 2\(\dfrac{3}{4}\)
c) x : 4\(\dfrac{1}{3}\) = - 2,5
d) (\(\dfrac{3x}{7}\) + 1) : (-4) = \(\dfrac{-1}{28}\)
giúp em
làm đầy đủ theo các bước nhé
Tìm x biết :
a) \(^{\dfrac{4}{9}+x=\dfrac{5}{3}}\)
b)\(\dfrac{3}{4}.x=\dfrac{-1}{2}\)
c) \(\dfrac{3}{7}+\dfrac{5}{7}:x=\dfrac{1}{3}\)
d)\(3\dfrac{1}{4}:\left|2x-\dfrac{5}{12}\right|=\dfrac{39}{16}\)
Bài 1: Tìm x, biết
a)\(\dfrac{-2}{3}\)- \(\dfrac{1}{3}\) (2x-5) = \(\dfrac{3}{2}\)
b)\(\dfrac{2}{5}\) .x +\(\dfrac{1}{2}\) = \(\dfrac{-3}{4}\)
giúp em
16 tháng 7 2021 lúc 7:19
tìm x biết :
a) \(\left|x+\dfrac{1}{2}\right|\)=\(\dfrac{5}{2}\) b) \(\left|2x-\dfrac{2}{3}\right|\)+\(\dfrac{1}{3}\)=0 c) |x-2| = 2x + 1
\(\color{red}{\text{Tìm X }}\):
\(a) |x|=\)\(\dfrac{1}{5}\)\(+\)\(\dfrac{3}{4}\)
\(b)|x-5|=-\)\(\dfrac{5}{3}+\dfrac{1}{4}\)
\(\color{red}{\text{Giúp em với ak}}\)
Tìm số nguyên \(x\), biết rằng :
\(4\dfrac{1}{3}.\left(\dfrac{1}{6}-\dfrac{1}{2}\right)\le x\le\dfrac{2}{3}.\left(\dfrac{1}{3}-\dfrac{1}{2}-\dfrac{3}{4}\right)\)
1\(\dfrac{3}{5}\) + 0,25 x \(\dfrac{16}{15}\)- \(\dfrac{13}{15}\)
Tìm x biết :
a)\(\dfrac{3x}{5}=\dfrac{1-4x}{3}\)
b)\(\dfrac{x}{5}=\dfrac{15}{3x}\)
\(G=\dfrac{2}{5.8}+\dfrac{2}{8.11}+...+\dfrac{2}{95.98}+\dfrac{2}{98.101}\)
\(X=\dfrac{2^2}{1.3}.\dfrac{3^2}{2.4}.\dfrac{4^2}{3.5}...\dfrac{99^2}{98.100}\)
\(K=\dfrac{1}{3}.\dfrac{1}{15}.\dfrac{1}{35}...\dfrac{1}{9999}\)