Question

\(\color{red}{\text{Tìm X }}\):

\(a) |x|=\)\(\dfrac{1}{5}\)\(+\)\(\dfrac{3}{4}\)

\(b)|x-5|=-\)\(\dfrac{5}{3}+\dfrac{1}{4}\)

\(\color{red}{\text{Giúp em với ak}}\)

 

Answer 1

a \(\Rightarrow\left|x\right|=\dfrac{19}{20}\Rightarrow\left[{}\begin{matrix}x=\dfrac{19}{20}\\x=-\dfrac{19}{20}\end{matrix}\right.\)

b \(\Rightarrow\left|x-5\right|=-\dfrac{17}{12}\) vô lí vì\(VT=\left|x-5\right|\ge0\) mà \(VP=-\dfrac{17}{20}< 0\) 

\(\Rightarrow\) ko có x

Answer 2

a/ /x/= \(\dfrac{1}{5}+\dfrac{3}{4}\)

/x/= 0.95

=> x= \(\pm0.95\)

Vạy....

b/ /x-5/ =\(-\dfrac{5}{3}+\dfrac{1}{4}\)

/x-5/ =\(-\dfrac{17}{12}\) (vô lý)

Vậy...