2:
a: =>x=1/2+1/6=3/6+1/6=4/6=2/3
b: =>x+3,5=7,8-6,3=1,5
=>x=1,5-3,5=-2
c: =>(35-x)/-105=1/5
=>35-x=-21
=>x=56
1
c hình như tính bình thường thôi:v
d
= 1,75 : 5 + 2,5 . (16 – 4 . 4,1)
= 1,75 : 5 + 2,5 . (16 – 16,4)
= 1,75 : 5 + 2,5 . (−0,4)
= 0,35 − 1
= −0,65.
2
a
\(\Rightarrow x=\dfrac{1}{2}+\dfrac{1}{6}=\dfrac{3}{6}+\dfrac{1}{6}=\dfrac{4}{6}=\dfrac{2}{3}\)
b
\(\Rightarrow x+\dfrac{35}{10}=\dfrac{78}{10}-\dfrac{63}{5}:2\\ \Rightarrow x+\dfrac{35}{10}=\dfrac{78}{10}-\dfrac{63}{10}=\dfrac{15}{10}\\ \Rightarrow x=\dfrac{15}{10}-\dfrac{35}{10}=-2\)
c không rõ đề:v
\(1,\dfrac{2}{-11}.6\dfrac{2}{7}+\dfrac{3}{7}:3+5\\ =\dfrac{2}{-11}.\dfrac{44}{7}+\dfrac{3}{7}\times\dfrac{1}{3}+5\\ =-\dfrac{88}{77}+\dfrac{3}{21}+5\\ =-\dfrac{8}{7}+\dfrac{1}{7}+5\\ =-1+5\\ =4\)
\(d,1,75:5+2,5.\left(4^2-4.4,1\right)\\ =0,35+2,5.\left(16-16,4\right)\\ =0,35+2,5.0,4\\ =0,35+1\\ =1,35\)
`2,`
`a, 1/2 -x=-1/6`
`=> x= 1/2 -(-1/6)`
`=> x= 1/2 +1/6`
`=> x= 3/6+1/6`
`=>x= 4/6`
`=>x=2/3`
Vậy `x=2/3`
`b, x+3,5 =7,8 -12,6 :2`
`=> x+3,5 = 7,8 - 6,3`
`=> x+3,5=1,5`
`=> x= 1,5-3,5`
`=>x=-2`
Vậy `x=-2`
\(c,\dfrac{7}{35}=\dfrac{35-x}{-105}\\ \Rightarrow7.\left(-105\right)=35.\left(35-x\right)\\ \Rightarrow-735=1225-35x\\ \Rightarrow-735-1225=-35x\\ \Rightarrow-1960=-35x\\ \Rightarrow x=-1960:\left(-35\right)\\ \Rightarrow x=56\)
Vậy `x=56`
1, Mình tính thường nhé ạ, tại nhìn đề hình như tính bthường hết á cậu:').
\(c,\dfrac{2}{-11}\cdot6\dfrac{2}{7}+\dfrac{3}{7}:3+5=\dfrac{2}{-11}\cdot\dfrac{44}{7}+\dfrac{3}{7}\cdot\dfrac{1}{3}+5\)
\(=\dfrac{88}{-77}+\dfrac{3}{21}+5=\dfrac{8}{-7}+\dfrac{1}{7}+5=-1+5=4\)
`---`
\(d,1,75:5+2,5\cdot\left(4^2-4\cdot4,1\right)=0,35+2,5\cdot\left(16-16,4\right)\)
\(=0,35+2,5\cdot\left(0,4\right)=0,35+\left(-1\right)=-0,65\)
2,
\(a,\dfrac{1}{2}-x=-\dfrac{1}{6}\)
\(x=\dfrac{1}{2}-\left(-\dfrac{1}{6}\right)\)
\(x=\dfrac{6}{12}-\left(-\dfrac{2}{12}\right)\)
\(x=\dfrac{8}{12}=\dfrac{2}{3}\)
Vậy `x=2/3`
`---`
\(b,x+3,5=7,8-12,6:2\)
`x+3,5=7,8-6,3`
`x+3,5=1,5`
`x=1,5-3,5`
`x=-2`
Vậy `x=-2`
`---`
\(c,\dfrac{7}{35}=\dfrac{35-x}{-105}\)
\(\text{[}7\left(-105\right)\text{]}=35\left(35-x\right)\)
\(-735=35\left(35-x\right)\)
\(-\dfrac{735}{35}=35-x\)
\(-21=35-x\)
`x = 35 - (-21)`
`x = 35 + 21`
` x = 56`
Vậy `x=56`
#Tks_DN