`x/2 = 9/(2x)`
`2x^2 = 2*9`
`x^2 = 9`
`x^2 = (+-3)^2`
`=> x=+-3`
Vậy `x=+-3`
\(\dfrac{x}{2}=\dfrac{9}{2x}\\ \Rightarrow2x^2=18\\ \Rightarrow x^2=18:2=9\\ \Rightarrow x=3\)
x.2x=9.2
x2.2=18
x2=9
x2=32
x=3
\(< =>x\cdot2x=9\cdot2=2x^2=18< =>x^2=9< =>x\in\left\{-3;3\right\}\)
\(\Rightarrow2x.x=2.9\)
\(\Leftrightarrow3x=18\)
\(\Leftrightarrow x=6\)