\(\dfrac{x^2}{6}=\dfrac{24}{25}\\ \Leftrightarrow25x^2=6\cdot24\\ \Leftrightarrow25x^2=144\\ \Leftrightarrow x^2=5,76\\ \Leftrightarrow\left[{}\begin{matrix}x=2,4\\x=-2,4\end{matrix}\right.\)
\(x^2.25=6.24\)
\(x^2.25=144\)
\(x^2=144:25\)
\(x^2=5,67\)
\(x=\sqrt{5,67}=2,4;-2,4\)
x2/6 = 24/25
=> x2 = 24 x 6 /25 = 144/25 => x ⊥ √144/25 ⊥ 12/5
vậy x = 12/5
x\(^2\)/26=24/25
⇒25x\(^2\)=6⋅24
⇔25x\(^2\)=144
⇔x\(^2\)=5,76
\(\left\{{}\begin{matrix}x=2,4\\x=-2,4\end{matrix}\right.\)
