Question

\(\dfrac{x-2}{x+3}+\dfrac{x+5}{x+3}\)

a, Cộng hai phân thức 

b, Tìm ĐKXD

Answer 1

a)\(=\dfrac{x-2+x+5}{x+3}=\dfrac{2x+3}{x+3}\)

b)ĐKXĐ: \(x+3\ne0\Leftrightarrow x\ne-3\)

Answer 2

a) Ta có: \(\dfrac{x-2}{x+3}+\dfrac{x+5}{x+3}\)

\(=\dfrac{x-2+\left(x+5\right)}{x+3}\)

\(=\dfrac{x-2+x+5}{x+3}\)

\(=\dfrac{2x+3}{x+3}\)

b) ĐKXĐ: \(x+3\ne0\)

hay \(x\ne-3\)