Question

\(\dfrac{x-1}{x+5}=\dfrac{6}{7}\left(x\ne5\right)\Rightarrow x=?????\)

Answer 1

\(\Leftrightarrow7\cdot\left(x-1\right)=6\cdot\left(x+5\right)\)

\(\Leftrightarrow7x-7-6x-30=0\)

\(\Leftrightarrow x-37=0\)

\(\Leftrightarrow x=37\left(N\right)\)

Answer 2

Ta có: \(\dfrac{x-1}{x+5}=\dfrac{6}{7}\)

\(\Leftrightarrow7x-7-6x-30=0\)

\(\Leftrightarrow x=37\)