Question

\(\dfrac{\left(x+2\right)^2}{32}=\dfrac{2}{x+2}\)

Answer 1

\(\dfrac{\left(x+2\right)^2}{32}=\dfrac{2}{x+2}\)

<=> (x+2)² . x+2 = 2 . 32

(x+2)³ = 64

(x+2)³ = 4³

=> x+2 = 4

x = 4 - 2

x = 2

Answer 2

\(\dfrac{\left(x+2\right)^2}{32}=\dfrac{2}{x+2}\left(x\ne-2\right)\)

\(\Leftrightarrow\left(x+2\right)^3=64\)

\(\Leftrightarrow x+2=4\)

\(\Leftrightarrow x=2\left(TM\right)\)

Vậy PT có nghiệm là \(x=2\)