\(=\dfrac{-\dfrac{1}{5}+\dfrac{1}{7}+\dfrac{1}{8}}{\dfrac{-3}{5}+\dfrac{3}{7}+\dfrac{3}{8}}+\dfrac{\dfrac{1}{2}+\dfrac{1}{3}-\dfrac{1}{5}}{\dfrac{3}{4}+\dfrac{3}{6}-\dfrac{3}{10}}\)
\(=\dfrac{-1}{-3}+1:\dfrac{3}{2}=\dfrac{1}{3}+\dfrac{2}{3}=1\)
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