Question

\(\dfrac{9^{14}}{3^{12}.27^6}\)

Answer 1

\(\dfrac{9^{14}}{3^{12}.27^6}=\dfrac{3^{28}}{3^{12}.3^{18}}=\dfrac{3^{28}}{3^{28}.3^2}=\dfrac{1}{3^2}=\dfrac{1}{9}\)

Answer 2

\(\dfrac{9^{14}}{3^{12}.27^6}=\dfrac{\left(3^2\right)^{14}}{3^{12}.\left(3^3\right)^6}\\ =\dfrac{3^{28}}{3^{12}.3^{18}}\\ =\dfrac{3^{28}}{3^{30}}=\dfrac{1}{3^2}\\ =\dfrac{1}{9}\)