Question

\(\dfrac{6^3+3\times6^3+3^3}{13}\)

Answer 1

Ta có : \(\dfrac{6^3+3.6^3+3^3}{13}=\dfrac{6^3.\left(1+3\right)+3^3}{13}=\dfrac{6^3.4+3^3}{13}\)

=> \(\dfrac{\left(3.2\right)^3.4+3^3}{13}=\dfrac{3^3.2^3.4+3^3}{13}=\dfrac{3^3.2^5+3^3}{13}\)

=> \(\dfrac{3^3.\left(2^5+1\right)}{13}=\dfrac{3^3.33}{13}=\dfrac{891}{13}\)

Answer 2

\(\dfrac{6^3+3\times6^3+3^3}{13}\)

= \(\dfrac{216+648+27}{13}\)

= \(\dfrac{891}{13}\)
@Trịnh Thị Thảo Nhi