\(\dfrac{3x^2+3x}{x+1}=\dfrac{3x\left(x+1\right)}{x+1}=3x\)
Chúc cậu học tốt
3x2+3xx+1
3x(x+1)x+1 \dfrac{3x^2+3x}{x+1}=?
31=3 \dfrac{3x^2+3x}{x+1}=?
\dfrac{3x^2+3x}{x+1}=?
\(\dfrac{3x^2+3x}{x+1}=\dfrac{3x\left(x+1\right)}{x+1}=\dfrac{3x}{1}=3x\)