\(\dfrac{2}{3}x+\dfrac{1}{4}=\dfrac{7}{12}\)
\(\dfrac{2}{3}x=\dfrac{1}{3}\)
\(x=\dfrac{1}{3}:\dfrac{2}{3}\)
\(x=\dfrac{1}{2}\)
<=> \(\dfrac{2}{3}x\) = \(\dfrac{1}{3}\)
<=> x = \(\dfrac{1}{2}\)
\(\dfrac{2}{3}x+\dfrac{1}{4}=\dfrac{7}{12}\)
\(\dfrac{2}{3}x=\dfrac{7}{12}-\dfrac{1}{4}\)
\(\dfrac{2}{3}x=\dfrac{1}{3}\)
\(x=\dfrac{1}{3}:\dfrac{2}{3}\)
\(x=\dfrac{1}{2}\)