Câu hỏi của Bi Ly

Question

$\dfrac{1}{3}$- $\dfrac{2}{5}$+ 3x=$\dfrac{3}{4}$

nguyen khanh duy · Accepted Answer

$\dfrac{1}{3}-\dfrac{2}{5}+3x=\dfrac{3}{4}$

$3x=\dfrac{1}{3}-\dfrac{2}{5}-\dfrac{3}{4}$

$3x=-\dfrac{49}{60}$

$x=-\dfrac{49}{60}:3$

$x=-\dfrac{49}{180}$Câu trả lời: $\dfrac{1}{3}-\dfrac{2}{5}+3x=\dfrac{3}{4}$

$3x=\dfrac{1}{3}-\dfrac{2}{5}-\dfrac{3}{4}$

$3x=-\dfrac{49}{60}$

$x=-\dfrac{49}{60}:3$

$x=-\dfrac{49}{180}$

lê thị hương giang · Answer

$\dfrac{1}{3}-\dfrac{2}{5}+3x=\dfrac{3}{4}$

$\Rightarrow\dfrac{2}{5}+3x=\dfrac{1}{3}-\dfrac{3}{4}$

$\Rightarrow\dfrac{2}{5}+3x=-\dfrac{5}{12}$

$\Rightarrow3x=-\dfrac{49}{60}$

$\Rightarrow x=-\dfrac{49}{180}$Câu trả lời: $\dfrac{1}{3}-\dfrac{2}{5}+3x=\dfrac{3}{4}$

$\Rightarrow\dfrac{2}{5}+3x=\dfrac{1}{3}-\dfrac{3}{4}$

$\Rightarrow\dfrac{2}{5}+3x=-\dfrac{5}{12}$

$\Rightarrow3x=-\dfrac{49}{60}$

$\Rightarrow x=-\dfrac{49}{180}$

Trần Hương Thoan · Answer

$\dfrac{1}{3}-\dfrac{2}{5}+3x=\dfrac{3}{4}$

$\dfrac{3}{4}-3x=\dfrac{1}{3}-\dfrac{2}{5}$

$\dfrac{3}{4}-3x=-\dfrac{1}{15}$

$\dfrac{3}{4}+\dfrac{1}{15}=3x$

$\dfrac{49}{60}=3x$

$x=\dfrac{49}{180}$

Vậy $x=\dfrac{49}{180}$Câu trả lời: $\dfrac{1}{3}-\dfrac{2}{5}+3x=\dfrac{3}{4}$

$\dfrac{3}{4}-3x=\dfrac{1}{3}-\dfrac{2}{5}$

$\dfrac{3}{4}-3x=-\dfrac{1}{15}$

$\dfrac{3}{4}+\dfrac{1}{15}=3x$

$\dfrac{49}{60}=3x$

$x=\dfrac{49}{180}$

Vậy $x=\dfrac{49}{180}$

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