\(n_{O_2}=\dfrac{9.10^{22}}{6.10^{23}}=0,15\left(mol\right)\)
a) PTHH: 2KMnO4 -to-➤ K2MnO4 + MnO2 + O2
Theo PT : \(n_{KMnO_4}=2n_{O_2}=2.0,15=0,3\left(mol\right)\)
⇒ \(m_{KMnO_4}=0,3.158=47,5\left(g\right)\)
b) PTHH: 2KClO3 -to-➤ 2KCl + 3O2
Theo PT: \(n_{KClO_3}=\dfrac{2}{3}n_{O_2}=\dfrac{2}{3}.0,15=0,1\left(mol\right)\)
⇒ \(m_{KClO_3}=0,1.122,5=12,25\left(g\right)\)