nCa(OH)2= 0.01*0.3=0.003 mol
Ca(OH)2 + SO2 --> CaSO3 + H2O
0.003______0.003
VSO2= 0.003*22.4=0.672l= 672ml
TH1 : Chỉ tạo ra muối trung hòa
nCa(OH)2= 0.01*0.3=0.003 mol
Ca(OH)2 + SO2 --> CaSO3 + H2O
0.003_____0.003
VSO2= 0.003*22.4=0.672l=672 ml
TH2: Tạo ra cả 2 muối
Ca(OH)2 + SO2 --> CaSO3 + H2O
0.003_____0.003____0.003
CaSO3 + SO2 + H2O --> Ca(HSO3)2
0.003____0.003
nSO2= 0.003+0.003=0.006 mol
VSO2= 0.006*22.4=0.1344l=134.4ml