nCuO = 0,8 mol
\(CuO+H_2\underrightarrow{t^o}Cu+H_2O\)
⇒ mCu = 0,8.64 = 51,2 (g)
Zn + 2HCl \(\rightarrow\) ZnCl2 + H2
\(\Rightarrow\) mZn = 0,8.65 = 52 (g)
a.PTHH:CuO+H2----->Cu+H2O (1)
b.\(n_{CuO}=\dfrac{m}{M}=\dfrac{64}{80}=0,8\left(mol\right)\)
Theo PTHH (1):nCu=nCuO=0,8mol
\(m_{Cu}=n.M=0,8.64=51,2\left(g\right)\)
c.Theo PTHH (1):\(n_{H_2}=n_{CuO}=0,8\left(mol\right)\)
PTHH:Zn+2HCl----->ZnCl2+H2 (2)
Theo PTHH (2):\(n_{Zn}=n_{H_2}=0,8\left(mol\right)\)
\(m_{Zn}=n.M=0,8.65=52\left(g\right)\)
nCuO=64/80=0.8(mol)
a) PTHH: CuO + H2 ---> Cu + H2O
0.8 0.8 0.8 0.8 (mol)
b) mCu=0.8*64=51.2(g)
c) Zn + 2HCl ---> ZnCl2 + H2
0.8 0.8 (mol)
mZn=0.8*65=52(g)
Mong mn tích cho mik nha