Ta có:
\(n_{Br2}=0,15.1=0,15\left(mol\right)\)
\(C_2H_4+Br_2\rightarrow C_2H_4Br_2\)
0,15_____0,15______
\(V_{C2H4}=0,15.22,4=3,36\left(l\right)\)
\(\Rightarrow\left\{{}\begin{matrix}\%V_{C2H4}=\frac{3,36.100}{89}=3,7753\%\\\%V_{CH4}=100\%-3,7753\%=96,2247\%\end{matrix}\right.\)
\(V_{CH4}=89-3,36=85,64\left(l\right)\)
\(\Rightarrow n_{CH4}=\frac{85,64}{22,4}=3,82\left(mol\right)\)
\(CH_4+2O_2\rightarrow2H_2O+CO_2\)
3,82_____________________3,82
\(C_2H_4+3O_2\rightarrow2CO_2+2H_2O\)
0,15_____________0,3___________
\(\Rightarrow n_{CO2}=0,3+3,82=4,12\left(mol\right)\)
\(Ca\left(OH\right)_2+CO_2\rightarrow CaCO_3+H_2O\)
_________ 4,12 ____4,12_____________
\(\Rightarrow m_{CaCO3}=4,12.100=412\left(g\right)\)
