\(n_{CO2}=\frac{5,6}{22,4}=0,25\left(mol\right)\)
\(n_{NaOH}=0,15.2=0,3\)
Ta có \(T=\frac{n_{NaOH}}{n_{CO2}}=\frac{0,3}{0,25}=1,2\)
Mà 1 < T < 2
\(\Rightarrow\) Tạo hai muối Na2CO3 và NaHCO3
\(PTHH:CO_2+2NaOH\rightarrow Na_2CO_3+H_2O\)
______a_________2a__________a_______________
\(CO_2+NaOH\rightarrow NaHCO_3\)
b______b ______________b
\(\left\{{}\begin{matrix}a+b=0,25\\2a+b=0,3\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}a=0,05\\b=0,15\end{matrix}\right.\)
\(m_{Na2CO3}=0,05.106=5,3\left(g\right)\)
\(m_{NaHCO3}=0,15.84=12,6\left(g\right)\)
